We can use the previous approach, where we calculated all sum subarray using Carry Forward technique. Instead of keeping track of maximum, we can simply add the sums in a variable. Instead of ...
[ 1 2 3 ] [ 4 5 6 ] [ 7 8 9 ] The answer should be 5 since the longest path would be 1-2-5-6-9]() import heapq def max_three(arr): a = heapq.nlargest(3, arr ...
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