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1:50
Q) If π ππ πππ‘^(β1) (π₯+1)]=πππ (tan^(β1) π₯), π‘βππ ππππ π₯.#class12maths #shivang
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Q) Let f: π _+ β [-5, β) be defined as f(x) = γ9π₯γ^2+6π₯β5, where π _+ is the set of al non-negat
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Q) Simplify :sin(cot^(β1) π₯)}}#class12maths #shivangmathsacademy #cbsemaths #class12 #Shivangmath
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Q) Check whether function f(x) defined as f(π₯)={((|π₯β3|)/(2(π₯β3)), π₯=3 (π₯β6)/6,π₯β₯3) Is
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Q) The value of π for which the function π(π₯)={(π₯^2 sin 1/π₯, π₯β 0 π(π₯+1), π₯=0) is a continuo
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Q) A Show that a function f: R β R defined as f(x) = π₯^2+π₯+1 is neither one-one nor onto. Also,
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1:07
Q) If π(π₯)={(sinπ₯/π₯+cosπ₯, π₯β 0 π, π₯=0) is continuous at π₯=0, then the value of π is :
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Vlookup in excel #excel #computer #shortfeed #vlog #jictcomputer
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Q) Simplify: ππ¨π¬^(βπ) π±+ππ¨π¬^(βπ) [π±/π+β(πβππ±^π )/π]; π/πβ€π±β€π #cbsemaths #maths
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Q) If π(π₯)={ ((π₯^2β4π₯β5)/(π₯+1), π₯β β1 π,&π₯=β1 is continuous at π₯=β1, then the value of π i
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1:53
Q) If π(π₯)={((1βsin^3 π₯)/(3cos^2 π₯), for π₯β π/2 π, for π₯=π/2) is continuous at π₯=π/2, t
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1:29
Q) Domain of π ππ^(β1) (2π₯^2β3) is (A) (β1,0)βͺ(1,β2)(B) (ββ2,β1)βͺ(0,1)(C) [ββ2,β1]βͺ[1,β2](D) (β
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Q) Show that the function π(π₯)={(cosπ₯/(βπ₯+π/2), π₯β π/2 1, π₯=π/2 is continuous at x=π/2.
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